Question
If in the number '526215743', 1 added to all the odd
numbers, then what is the sum of the digits which are repeating more than two times in the new number thus formed? Note: While taking the sum the repeating digit is to be considered only once.Solution
5Â Â Â Â Â Â Â Â Â 2Â Â Â Â Â Â Â Â Â 6Â Â Â Â Â Â Â Â Â 2Â Â Â Â Â Â Â Â Â 1Â Â Â Â Â Â Â Â Â 5Â Â Â Â Â Â Â Â Â 7Â Â Â Â Â Â Â Â Â 4Â Â Â Â Â Â Â Â Â 3Â Â Â Â Â Â Â Â Â 6Â Â Â Â Â Â Â Â Â 2Â Â Â Â Â Â Â Â Â 6Â Â Â Â Â Â Â Â Â 2Â Â Â Â Â Â Â Â Â 2Â Â Â Â Â Â Â Â Â 6Â Â Â Â Â Â Â Â Â 8Â Â Â Â Â Â Â Â Â 4Â Â Â Â Â Â Â Â Â 4 So, the digits that are repeating more than two times are '6' and '2'. So, sum = (6 + 2) = 8
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57, 59, 56, 61, 54, ___
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