Question

    Given below are four combinations [i], [ii], [iii] and

    [iv] of five words. In each combination you have to arrange the letters in English alphabetical order from left to right. Then in each combination the first letter from the left end is numbered as I, the second letter from the left end is numbered as II and so on. Hence in each combination I, II, III, IV, and V will denote the position of the letters from the left end. [i] HEBVL [ii] OAFHP [iii] GESVB [iv] DWLGS From each of the given words, the letters, which are at the same positions are clubbed together. The letters which are at position [I] will form a word if taken in order of combination [i], [ii], [iii], and [iv] respectively and similarly form [I II III IV and V]. Then, how many meaningful words will be formed? TYPE - 7
    A Only I Correct Answer Incorrect Answer
    B Only I and II Correct Answer Incorrect Answer
    C Only II, III and IV Correct Answer Incorrect Answer
    D Only V, IV, II and I Correct Answer Incorrect Answer
    E Only IV Correct Answer Incorrect Answer

    Solution

    Arranging the letter in English alphabetical order, we get: [i] HEBVL - BEHLV [ii] OAFHP – AFHOP [iii] GESVB – BEGSV [iv] DWLGS – DGLSW On clubbing together in (I, II, III, IV, and V) from the left end, we get: Only IV will make a meaningful word i.e. ‘LOSS’.

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