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    Question

    If BOLT is coded as 147 and SHARP is coded as 186, then

    how will GLOVE be coded as?
    A 183 Correct Answer Incorrect Answer
    B 201 Correct Answer Incorrect Answer
    C 156 Correct Answer Incorrect Answer
    D 213 Correct Answer Incorrect Answer

    Solution

    The logic followed here is: (Sum of the place values of all letters) Γ— 3 = Code. For BOLT β†’ [B(2) + O(15) + L(12) + T(20] x 3 = 49 x 3 = 147 For SHARP β†’ [S(19) + H(8) + A(1) + R(18) + P(16)] x 3 = 62 x 3 = 186 For GLOVE β†’ [G(7) + L(12) + O(15) + V(22) + E(5)] x 3 = 61 x 3 = 183

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