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      Question

      If BOLT is coded as 147 and SHARP is coded as 186, then

      how will GLOVE be coded as?
      A 183 Correct Answer Incorrect Answer
      B 201 Correct Answer Incorrect Answer
      C 156 Correct Answer Incorrect Answer
      D 213 Correct Answer Incorrect Answer

      Solution

      The logic followed here is: (Sum of the place values of all letters) Γ— 3 = Code. For BOLT β†’ [B(2) + O(15) + L(12) + T(20] x 3 = 49 x 3 = 147 For SHARP β†’ [S(19) + H(8) + A(1) + R(18) + P(16)] x 3 = 62 x 3 = 186 For GLOVE β†’ [G(7) + L(12) + O(15) + V(22) + E(5)] x 3 = 61 x 3 = 183

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