Question
In a certain coding system, 'paper pencil eraser' is
coded as 'sd er nm'. 'book machine paper' is coded as 'nj sd cv' and 'tool pencil machine' is coded as 'er nj ty'. How will 'book eraser tool machine' is coded in this coding system?Solution
I. 'paper pencil eraser' is coded as 'sd er nm'. II. 'book machine paper' is coded as 'nj sd cv'. III. 'tool pencil machine' is coded as 'er nj ty'. After decoding the codes, we get, From Statement I and II, we get 'paper' is coded as 'sd'. From Statement I and III, we get 'pencil' is coded as 'er'. From Statement I alone, we get 'eraser' is coded as 'nm'. From Statement II and III, we get 'machine' is coded as 'nj From Statement II alone, we get 'book' is coded as 'cv'. From Statement III alone, we get 'tool' is coded as 'ty'. Therefore, 'book eraser tool machine' is coded as 'cv nm ty nj'.
?% of 18% of 2600 = 234
?² = 37% of 800 – 14 × 18+ 5! - 20
The value of 11 × 11 + 11 ÷ 11 – 11 × 11 + 11 + 11 × 11 – 11 – 11 × 11 is:
What will come in the place of question mark (?) in the given expression?
(286 ÷ 13 + 83) ÷ 15 × 8 + 84 = 400% of ?
436 × 794 – 68210 =? + 85730
70 % of 640 + 75 % of 360 - 19 × 12 = ?
What will come in the place of question mark (?) in the given expression?
737 + 149 - ?²- 367 = 14 X 25(62 - 52 ) % of 800 = 22 X √?
182 + 10 × 12 - ? = 312
560 ÷ 14 × 3 – 25 = ?