Question
Joseph's watch perform 2 min slow at 4 p.m. on Sunday.
It is observed that this watch performs 4 minute faster at 4 p.m. on Monday. Then find on which day and what time this watch performs correct time?Solution
Time Fluctuation = 2 min + 4 min = 6 minute Time duration = 4 pm (Sunday) to 4 pm (Monday) = 24 hours 6 minutes = 24 hours 1 minute = 4 hours Sunday 4 pm + 8 hours = 12 a.m. Right time = Sunday 12 a.m.
Which two signs should be interchanged to make the given equation correct?
12 ÷ 2 × 6 + 4 – 2 = 13
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