Question
Joseph's watch perform 2 min slow at 4 p.m. on Sunday.
It is observed that this watch performs 4 minute faster at 4 p.m. on Monday. Then find on which day and what time this watch performs correct time?Solution
Time Fluctuation = 2 min + 4 min = 6 minute Time duration = 4 pm (Sunday) to 4 pm (Monday) = 24 hours 6 minutes = 24 hours 1 minute = 4 hours Sunday 4 pm + 8 hours = 12 a.m. Right time = Sunday 12 a.m.
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Statement:
A. Some leopards are buffaloes.
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Conclusion:
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Change the question mark with the option that follows the applied logic in the first pair.
209 : 55 :: 579 : ??
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