Question
What is the smallest number that should be subtracted
from 1798425 so that the resulting number is divisible by 8?Solution
We have, 1798425 ÷ 8 = 224803.125 So, remainder when 1798425 is divided by 8 = 0.125 X 8 = 1 Therefore, smallest number that must be subtracted = 1
Output of below code
public class Prg {
public static void main(String args[]){
System.out.print("A" + "B" + 'A');
}
...The Master Theorem gives time complexity for recurrences of the form:
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