Question
If 'C' is coded as '6' and 'CAT' is coded as '48', then
how will 'CATTLE' be coded?Solution
The logic followed is:Each letter's positional value in the alphabet is added together and then multiplied by 2. C = 3 × 2 = 6 CAT = (3 + 1 + 20) × 2 = (24) × 2 = 48 CATTLE = (3 + 1 + 20 + 20 + 12 + 5) × 2 = 61 × 2 = 122
Statements: B & C, C # D, D @ E, E % F
Conclusions: I.   C & F                    II. E # B
...Statements: X ≥ W, W ≤ U, U > T, T < S
Conclusions: I) X > U
II) S > U
III) T < W
Statements :
A > B > C
Y > B
D > C > Z
Conclusions :
I. Z > D
II. Y > A
III. B > Z
...Statements: E > F = G; H < I = F; J > IÂ
Conclusions: I) J > GÂ
II) E < JÂ
III) H > E
Statements: A < B; C = D; B >E ≥ C
Conclusions:
I. A < C
II. E = D
Statements: D ≤ P > J > N > G, P ≤ R < V, N < K
Conclusions:
I. J < V
II. D > G
Statements:
A = B ≤ Y < Z; P ≤ I < A; M ≤ Y < N
Conclusions:
I). Â M < Z
II). Â P < Y
III). Â N > A
...Statements: G@B; W#Z; B%W
Conclusions:
I) G@Z
II) Z@B
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In the following question the relationship between different elements is given in the statements followed by three conclusions I, II and III. Read the...