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Tx is at one extreme end. Px is the neighbour of Tx and is third to the left of Qx. This implies that Tx sits at extreme left end, and Px sits to the immediate right of Tx. Also, Qx sits at the extreme right end. 
Thus, the arrangement can be show as below: Therefore, it is clear that Qx is fourth to the right of Tx. Hence, the correct answer is (C).
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