Question
Px, Qx, Rx, Sx and Tx are sitting together. Tx is at one extreme end. Px is the neighbour of Tx and is third to the left of Qx. Who is fourth to the right of Tx?
Thus, the arrangement can be show as below: Therefore, it is clear that Qx is fourth to the right of Tx. Hence, the correct answer is (C).More Aplhabetical Coding Questions
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