Question
If 45 @ 6 = 81 and 78 @ 9 = 159, then 115 @ 11 =
?Solution
The logic followed here is: The square of the second number is added to the first number to get the resultant number. In '45 @ 6 = 81': LHS: 45 + 6Β² = 45 + 36 = 81 LHS = RHS In '78 @ 9 = 159': LHS: 78 + 9Β² = 78 + 81 = 159 LHS = RHS Similarly, in '115 @ 11 = ?': LHS: 115 + 11Β² = 115 + 121 = 236 So, '115 @ 11 = 236'. Hence, option b.
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