Question
62 people are participating in a tournament. Each one
has to play with every other person. If 20 persons are disqualified before the start of the tournament, then how many games would be played in the tournament?Solution
Initially, there are 62 persons participating in the tournament. However, 20 persons are disqualified. Remaining persons = 62 - 20 = 42 So, the number of games to be played = (42 X 41) ÷ 2 The number of games to be played = 21 X 41 = 861 Thus, 861 games would now be played in the tournament.
Nucleosome is :Â
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