Four number-pairs are given, out of which three are

Solution

The logic followed here is as follows: The square of each digit of the 1st number is added together and then, the resultant is multiplied by 2 to obtain the 2nd number. 379: 278 → [2 × {(3)² + (7)²+ (9)² }] = [2 × {9 + 49 + 81}]= [2 × 139] = 278 663: 162 → [2 × {(6)² + (6)² + (3)² }] = [2 × {36 + 36 + 9}]= [2 × 81] = 162 746: 202 → [2 × {(7)² + (4)² + (6)² }] = [2 × {49 + 16 + 36}]= [2 × 101] = 202 498: 382 → [2 × {(4)² + (9)² + (8)² }] = [2 × {16 + 81 + 64}]= [2 × 161] = 322 ≠ 382