The difference between compound interest and simple interest at rate of 22% per annum for 2 years is Rs. 484. Find the simple interest obtained on same amount for a period of 2 years at rate of 10% per annum.
Let, the amount be Rs. P. P[(1 + 22/100)2 – 1] – P × 22% × 2 = 484 P × 0.4884 – P × 0.44 = 484 P × 0.0484 = 484 P = 484 ÷ 0.0484 = Rs. 10000 Therefore, required interest = 10000 × 10% × 2 = Rs. 2000
[(288)2 ÷ 96 × ?] ÷ 44 = 432
5 9 30 115 582 3483
15 ...
16 17 25 ? 99 180
...3, 2, 3, 8, 31, ?
3, 7, 16, 35, ?, 153
24 25 46 ? 572 2885
...7, 8, 12, 21, 37, ?
43 44 48 ...
Find the maximum number of trees which can be planted, 25 meters apart, on the two sides of a straight road 2125 meters long
7 7 14 42 ? 840
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