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    Question

    Biz is older than Ciz but not as old as Diz. Eiz is not

    as old as Biz. Who is the oldest of all?
    A Biz Correct Answer Incorrect Answer
    B Eiz Correct Answer Incorrect Answer
    C Ciz Correct Answer Incorrect Answer
    D Diz Correct Answer Incorrect Answer

    Solution

    Biz is older than Ciz but not as old as Diz à Diz > Biz > Ciz   Eiz is not as old as Biz à Biz > Eiz   Thus, combining the above equations, we get: Diz > Biz > Eiz, Ciz   Therefore, Diz is the oldest of all. Hence, the correct answer is (D).

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