Question
If 32 @ 10 = 32 and 42 @ 30 = 76, then 28 @ 56 =
'?'.Solution
{(3 x 2) + 10} x 2 = {6 + 10} x 2 = 16 x 2 = 32 {(4 x 2) + 30} x 2 = {8 + 30} x 2 = 38 x 2 = 76 {(2 x 8) + 56} x 2 = {16 + 56} x 2 = 72 x 2 = 144
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