Question
If 38 Γ 34 = 31, 34 Γ 58 = 25 and 56 Γ 67 = 43, then
28 Γ 32 = ?Solution
38 Γ 34 β (3 Γ 8) + 3 + 4 = 24 + 7 = 31 34 Γ 58 β (3 Γ 4) + 5 + 8 = 12 + 13 = 25 56 Γ 67 β (5 Γ 6) + 6 + 7 = 30 + 13 = 43 28 Γ 32 β (2 Γ 8) + 3 + 2 = 16 + 5 = 21
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