Question
If A is coded as ‘+’, C is coded as ‘÷’, B is
coded as ‘×’ and D is coded as ‘-’, then what is the value of 12 A 5 B 32 C 4 D 10 A 56 C 8 = ?Solution
12 A 5 B 32 C 4 D 10 A 56 C 8 = ? 12 + 5 × 32 ÷ 4 – 10 + 56 ÷ 8 12 + 5 × 8 – 10 + 7 12 + 40 – 10 + 7 52 – 3 = 49
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