Question
If A is coded as β+β, C is coded as βΓ·β, B is
coded as βΓβ and D is coded as β-β, then what is the value of 12 A 5 B 32 C 4 D 10 A 56 C 8 = ?Solution
12 A 5 B 32 C 4 D 10 A 56 C 8 = ? 12 + 5 Γ 32 Γ· 4 β 10 + 56 Γ· 8 12 + 5 Γ 8 β 10 + 7 12 + 40 β 10 + 7 52 β 3 = 49
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