Question
If 9sin²x + 5cos²x − 7 = 0, then find the value of
sinx, given that 0° < x < 90°.Solution
Given
9sin²x + 5cos²x = 7 Or,
9sin²x + 5(1 − sin²x) = 7 Or,
9sin²x + 5 − 5sin²x = 7 Or,
4sin²x = 2 Or,
sin²x = (1/2) Or,
sinx = (1/√2) (since, 0° < x < 90°)
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