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Since, ABC is a triangle,
So, ∠A + ∠B + ∠C = 180 ° .......... (I)
Also, ∠A - ∠C = 8 ° .......... (II)
On subtracting equation (II) from equation (I), we have;
2∠A + ∠B = 188 ° .......... (III)
Also, ∠A - ∠B = 16 ° ........ (IV)
On adding equation (III) and (IV), we have;
3∠A = 204 °
Or, ∠A = 68 °
So, ∠B = 68 ° - 16 ° = 52 °
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