Question
If cosec2A = (sin60o +
tan45o X sec245o), then find the value of sin2A.Solution
cosec2A = (sin60o + tan45o X sec245o),
coec2A = {(√3/2) + 1 X (√2)2}
cosec2A = {(√3 + 4)/2}
Since, sinA = (1/cosecA)
sin2A = [2/(√3 + 4)]
Rationalising by multiplying numerator and denominator by (4 - √3), we get= {2(4 - √3)/13}
More Trigonometry Questions
Evaluate: 360 ÷ [ {18 − (6×2)} × 5 ] + 72 − 33
(43)² - (28)² + (32)² = ?% of 2500
Evaluate:
√729 + √49 - √16 + 1/√64
What will come in place of (?) in the given expression.
12.5 + 7.75 - 3.6 = ?62 of 8 - 320 ÷ 4 = ?3 + 200
2(1/3) + 2(5/6) – 1(1/2) = ? – 6(1/6)
What will come in the place of question mark (?) in the given expression?
30% of 520 + 16% of 1500 = ? + 244
60% of 120 – ?% of 64 = 20% of 200
35% of 840 + 162 = ? – 25% × 300
20% of 240 + 18% of 200 = ?
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