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    Question

    If cosec2A = (sin60o +

    tan45o X sec245o), then find the value of sin2A.
    A 2(2 - √3) Correct Answer Incorrect Answer
    B 2(2 - √3)/13 Correct Answer Incorrect Answer
    C 2(4 - √3)/13 Correct Answer Incorrect Answer
    D 2(4 - √3) Correct Answer Incorrect Answer

    Solution

    cosec2A = (sin60o + tan45o X sec245o),

    coec2A = {(√3/2) + 1 X (√2)2}

    cosec2A = {(√3 + 4)/2}

    Since, sinA = (1/cosecA)

    sin2A = [2/(√3 + 4)]

    Rationalising by multiplying numerator and denominator by (4 - √3), we get= {2(4 - √3)/13}

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