Question
If cosec2A = (sin60o +
tan45o X sec245o), then find the value of sin2A.Solution
cosec2A = (sin60o + tan45o X sec245o),
coec2A = {(√3/2) + 1 X (√2)2}
cosec2A = {(√3 + 4)/2}
Since, sinA = (1/cosecA)
sin2A = [2/(√3 + 4)]
Rationalising by multiplying numerator and denominator by (4 - √3), we get= {2(4 - √3)/13}
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