Question
If sin(3x - 2o) = cos(2x + 22o),
then find the value of: {3tan(4x - 11o) + cosec(5x - 10o)} X cot(2x + 2o)Solution
sin (3x - 2o) = cos (2x + 22o), Or, sin (3x - 2o) = sin (90o - 2x - 22o) So, 3x - 2o = 68o - 2x So, 5x = 70o So, x = (70/5) = 14o So, {3tan (4x - 11o) + cosec (5x - 10o)} X cot (2x + 2o) = {3 X tan45o + cosec 60o} X cot30o = (3 X 1 + 2/√3) x √3 = {(3 √3  + 2)/ √3}  x √3 = (3 √3  + 2)Â
What will come in the place of questions (?) mark in the following questions.
53, 55, 61, 71, 85, ?
√(10198 )× √(7220 )÷ 16.69 + 2010.375= ?
7, 7, 14, 40, ?, 227
24, 42, 60, ?, 96, 114
196, 196, 203, 229, 292, ?
500, 250, 750, 375, 1125, 562.5, ?
22, 37, 63, 98, 148, ?
What will come in the place of questions (?) mark in the following questions.
1204, 1218, ? , 1267, 1302, 1344
- What will come in place of the question mark (?) in the following series?
13, 15, 18, 23, 30, ? What will come in place of the question mark (?) in the following series?
325, 292, 262, 229, ?, 166
