📢 Too many exams? Don’t know which one suits you best? Book Your Free Expert 👉 call Now!

    Question

    If sin(3x - 2o) = cos(2x + 22o),

    then find the value of: {3tan(4x - 11o) + cosec(5x - 10o)} X cot(2x + 2o)
    A 8√3 Correct Answer Incorrect Answer
    B 8√3 Correct Answer Incorrect Answer
    C 3√3 + 2 Correct Answer Incorrect Answer
    D 2√3 + 3 Correct Answer Incorrect Answer

    Solution

    sin (3x - 2o) = cos (2x + 22o), Or, sin (3x - 2o) = sin (90o - 2x - 22o) So, 3x - 2o = 68o - 2x So, 5x = 70o So, x = (70/5) = 14o So, {3tan (4x - 11o) + cosec (5x - 10o)} X cot (2x + 2o) = {3 X tan45o + cosec 60o} X cot30o  = (3 X 1 + 2/√3) x  √3 = {(3 √3  + 2)/ √3}  x  √3 =  (3 √3  + 2) 

    Practice Next
    More Trigonometry Questions
    ask-question