Question
If sin(3x - 2o) = cos(2x + 22o),
then find the value of: {3tan(4x - 11o) + cosec(5x - 10o)} X cot(2x + 2o)Solution
sin (3x - 2o) = cos (2x + 22o), Or, sin (3x - 2o) = sin (90o - 2x - 22o) So, 3x - 2o = 68o - 2x So, 5x = 70o So, x = (70/5) = 14o So, {3tan (4x - 11o) + cosec (5x - 10o)} X cot (2x + 2o) = {3 X tan45o + cosec 60o} X cot30o = (3 X 1 + 2/√3) x √3 = {(3 √3  + 2)/ √3}  x √3 = (3 √3  + 2)Â
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