Question
Find the value of sin265o +
sin225o + cos235o + cos255o.Solution
sin265o + sin225o + cos235o + cos255o Using sin(90o – x) = cosx and vice versa sin265o + sin2 (90o – 65o) + cos235o + cos2(90o – 35o) = sin265o + cos265o + cos235o + sin235o = 1 + 1 = 2 (since, sin2x + cos2x = 1)
 If 4x = 40, 3y = 33, what is the value of 6x + 4y?
I. 2y² - 3y – 14 = 0
II. 3x² - 7x + 4 = 0
If a quadratic polynomial y = ax2 + bx + c intersects x axis at a and β, then
I. 7x + 8y = 36
II. 3x + 4y = 14
I. 4p² + 17p + 15 = 0
II. 3q² + 19q + 28 = 0
The equation x2 – px – 60 = 0, has two roots ‘a’ and ‘b’ such that (a – b) = 17 and p > 0. If a series starts with ‘p’ such...
I. x2 + 16x + 63 = 0
II. y2 + 2y - 15 = 0
I. 40 x² - 93 x + 54 = 0
II. 30 y² - 61 y + 30 = 0
I. x + 1 = 3√ 9261
II. y + 1 = √ 324
I. 35x² - 24x – 35 = 0
II. 72y² - 145y + 72 = 0
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