Question
If secθ + tanθ = 3+√10, then the value
of sinθ+cosθ isSolution
secθ + tanθ = 3+√10 ............... (i) (sec²θ - tan²θ) = 1 (secθ + tanθ) (secθ - tanθ) = 1 (3+√10) (secθ - tanθ) = 1 secθ - tanθ = 1/(3+√10) = 1/(√10+3) secθ - tanθ = √10-3 ............ (ii) From (i) and (ii) we get, 2secθ = 2√10 secθ = √10 cosθ = 1/√10 sin²θ + cos²θ = 1 sin²θ + 1/10 = 1 sin²θ = 1- 1/10 = 9/10 sinθ = 3/√10 sinθ + cosθ = 3/√10 + 1/√10 = 4/√10 = 4/√10 × √10/√10 = (2√10)/5
What value should come in place of (?) question mark in the given expression.
17 × 15 − 96 ÷ 8 + 6² = ?
Evaluate: 144 ÷ 12 × 6 + 35 − 4²
What will come in the place of question mark (?) in the given expression?
21 × 18 + ? – 19 × 15 = 25 × 24
2916 ÷ 54 = ? + 27
√324 + √484 + 63 = ?2
What will come in the place of question mark (?) in the given expression?
{(2/15) + (12/25)} of 375 + 190 = ?% of 375
- What will come in place of the question mark (?) in the following questions?
100−[20+4×5]=? (72 × 52 + 1555 )/(79+60) = 2000 ÷ ?
72 × 2 = ? + 104 – 14
672 ÷ 28 × 24 + 363 – 309 =?
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