Question
In triangle ABC, DE is drawn parallel to side BC. If AD = 6
cm, DB = 4 cm and AE = 9 cm, then find AC.Solution
ATQ,
A line drawn parallel to one side of a triangle divides the other two sides in the same ratio.
(AD / DB) = (AE / EC)
=> (6 / 4) = (9 / EC)
=> EC = (9 Ă— 4) / 6 = 6 cm
So, AC = AE + EC = 9 + 6 = 15 cm
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