Question
A motorboat moves downstream at 30 km/h over a distance
of 480 km. After completing half the distance, the stream’s speed becomes 50% higher than before. Because of this, the boat reaches 30 minutes earlier than the usual time. Find the original speed of the stream.Solution
ATQ, Let the original speed of the stream be x km/h. Original time = 480/30 = 16 hours Time for first half = 16/2 = 8 hours New total time = 16 − 0.5 = 15.5 hours Time for second half = 15.5 − 8 = 7.5 hours Speed in second half = 240/7.5 = 32 km/h Net increase = 32 − 30 = 2 km/h So, 1.5x − x = 2 0.5x = 2 x = 4
I. 12x2 - 55x + 63 = 0
II. 10y2 - 47y + 55 = 0
I. 12a2 – 55a + 63 = 0
II. 8b2 - 50 b + 77 = 0
...I. 6p² + 17p + 12 = 0
II. 12q² - 25q + 7 = 0
If ‘y1’ and ‘y2’ are the roots of quadratic equation 5y2 – 25y + 15 = 0, then find the quadratic equation whose roots are ‘3y1�...
In the question, two equations I and II are given. You have to solve both the equations to establish the correct relation between 'p' and 'q' and choose...
In the question, two equations I and II are given. You have to solve both the equations to establish the correct relation between 'p' and 'q' and choose...
I. x2 – 39x + 360 = 0
II. y2 – 36y + 315 = 0
I. 5x² - 24 x + 28 = 0  Â
II. 4y² - 8 y - 12= 0  Â
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 41x + 400 = 0
Equation 2: y² - 41y + 420 = 0
I. 2x2 - 15x + 25 = 0
II. 3y2 - 10y + 8 = 0
