Question
The parallel sides of a trapezium and its height are in
an arithmetic progression with a common difference of 4. If the height is the highest term and the area of the trapezium is 160 sq. units, find the ratio of the length of the greatest parallel side to that of the smallest parallel side.Solution
ATQ,
Let sides be a+4 (parallel sides) and a+8 (height)
Area =
Sides: 8 and 12 ⇒ Ratio = 12/8 = 3:2
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