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Let the legs of the right-angled triangle be a and b, and the hypotenuse be c. Given: c = 20 cm and a = 12 cm. Using Pythagoras' theorem: c² = a² + b² 20² = 12² + b² 400 = 144 + b² b² = 256 b = 16 cm Area of the triangle = 1/2 × a × b Area = 1/2 × 12 × 16 = 96 cm² Correct option: B) 96 cm²
Find the value of (cos 60 º + sin 60 º) /(tan 60 º + cot 45 º) .
If sin θ = 3/5 and cos θ = 4/5, find the value of (2tan² θ + 3cot² θ).
If cosec (2A + B) = (2/√3) and cosec (A + B) = √2, then determine the value of (4A - B).
If sin 28° = 15/17 , then tan 62° = ?
tan 1˚ × tan 2˚× …………………….tan 88˚ × tan 89˚ = ?
If 2cosA + secA = 2√2 , 0° < < 90°, then the value of 2(sec 4 A + cosec 4 A) is: