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      Question

      Train 'R' is 280 meters long and it crosses a pole in

      14 seconds and it also passes Train 'S', which is moving in the opposite direction, in 14 seconds. If Train 'S' is 1.5 times as long as Train 'R', then find the distance travelled by Train S in 40 minutes.
      A 60 km Correct Answer Incorrect Answer
      B 66 km Correct Answer Incorrect Answer
      C 72 km Correct Answer Incorrect Answer
      D 78 km Correct Answer Incorrect Answer
      E 84 km Correct Answer Incorrect Answer

      Solution

      Speed of Train 'R' = 280 ÷ 14 = 20 m/s Length of Train 'S' = 1.5 × 280 = 420 meters Combined length of Train 'R' and 'S' = 280 + 420 = 700 meters Relative speed of train 'R' w.r.t train 'S' when travelling towards each other = 700 ÷ 14 = 50 m/s So, speed of Train 'S' = 50 - 20 = 30 m/s Therefore, distance covered by Train S in 40 minutes = 30 × 40 × 60 = 72,000 meters = 72 km

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