Question
A train passes a stationary pole in 18 seconds and
passes a bridge of length 540 metres in 45 seconds. What is the speed of the train in km/h?Solution
ATQ, Let speed of train = v m/s Let length of train = L metres From pole: L = v × 18 …(1) From bridge (length = 540 m): Distance covered = L + 540 = v × 45 …(2) Substitute L from (1) into (2): v × 18 + 540 = v × 45 540 = 45v − 18v = 27v v = 540 / 27 = 20 m/s Convert m/s to km/h: 20 × (18/5) = 72 km/h So, speed of the train = 72 km/h.
What is the value of sin(B – C) cos(A – D) + sin(A – B) cos(C – D) + sin(C – A) cos(B – D)?
If sec²x + csc²x = 10, find the value of tan²x + cot²x.
If A lies in the first quadrant and 6 tan A = 5, then the value of 8 sin A−4 cos A / cos A+2 sin A is :
- If sin (4A − 5B) = (√2/2) and cos (A + B) = (√2/2), where 0° < A, B < 90°, then find the value of ‘A’.
sin2 4˚ + sin2 6˚ + sin2 8˚ + sin2 10˚ + ……… + sin2 86˚ =?
if 7 sin 2 x + 2 cos 2 x = 4  then find tan x

If sin 23° = `12/13` , then tan 67° = ?
...The angle of elevation of the top of a 70 feet tall tower from the initial position of a person on the ground was 30°. She walked towards the tower in ...

Take θ = 450