Question
Train 'X' crosses a standing pole in 12 seconds. Another
train 'Y' crosses train 'X' in 24 seconds while running in opposite directions on parallel tracks. The lengths of train 'X' and train 'Y' are in the ratio 5:6. If train 'X' is running at a speed of 60 km/h, determine the speed of train 'Y' in km/h.Solution
ATQ,
Length of train 'X' = 12 × 60 × (5/18) = 200 m
Length of train 'Y' = (200/5) × 6 = 240 m
Let the speed of train 'Y' be 's' km/h.
ATQ,
(200 + 240) = 24 × (s + 60) × (5/18)
Or, (440/24) × (18/5) = (s + 60)
Or, s + 60 = 66
So, s = 66 - 60 = 6 km/h
116 x (2/3)% of 420 + 666 x (2/3)% of 186 = 457 x (1/7)% of 126 + 555 x (5/9)% of 198 + ?
108² + 99 X 98² =?
...2945 – 1508 + 3454 = ? + 2255
15 * 12 + 35% of 80 + 70% of 130 = ?
What will come in the place of question mark (?) in the given expression?
65% of 900 - 45% of 600 = ? X 3Â
√225 + 27 × 10 + ? = 320
46% of 13/92 × 24/91 × 3500 =?
What is 12% of 4% of 7% of 2 x 106 ?
- What will come in place of (?), in the given expression.
125% of 96 + 33% of 300 = ?