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Start learning 50% faster. Sign in nowATQ,
Length of train 'X' = 12 × 60 × (5/18) = 200 m
Length of train 'Y' = (200/5) × 6 = 240 m
Let the speed of train 'Y' be 's' km/h.
ATQ,
(200 + 240) = 24 × (s + 60) × (5/18)
Or, (440/24) × (18/5) = (s + 60)
Or, s + 60 = 66
So, s = 66 - 60 = 6 km/h
54% of 250 = 6 × 21 + √?
1(1/2)+ 11(1/3) + 111(1/2) + 1111(1/3) + 11111(1/2) = ?
(3/7) x 868 + 25% of 240 = (? + 65)
√4761 ÷ 23 + √12769 = ? × 58
(49 x ?) / 3.5 + 389 = 627
(15 × 16) + 242= ? × 16
(15/8) x [6924 – 2124] + 910 = ? + 190
√(82 × 7 × 52 - 175) = ?
52% of 400 + √(?) = 60% of 600 - 25% of 400