Question
The distance between city A and city B is 510 km. A
train leaves A at 6 a.m. at 60 km/h. Another train leaves B at 7:30 a.m. towards A at 90 km/h. When will they meet?Solution
Time gap = 1.5 hrs → Distance = 60 × 1.5 = 90 km
Remaining = 510 – 90 = 420 km
Relative speed = 150 km/h
Time = 420 / 150 = 2.8 hrs = 2h 48m
Meeting time = 7:30 a.m. + 2h 48m = 10:18 a.m.
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