Question
Train M, βxβ metres long crosses (x β 30) metres
long platform in 22 seconds while train N having the length (x + 30) metres crosses the same platform in 28 seconds. If the speeds of both trains are same then find the value of βxβ.Solution
Total distance travelled by train M = (2x β 30) m Total distance travelled by train N = (x + 30 + x β 30) = 2x m According to question, => (2x β 30)/22 = 2x/28 => 56x β 840 = 44x => 12x = 840 => x = 70 m
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