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Static friction, which prevents an object from moving when a force is applied, increases with the normal force exerted on the object's surface. The greater the normal force, the greater the static friction force opposing motion.
A person is standing at a point 120 meters away from a tower. The angle of elevation to the top of the tower is 60°. If the height of the tower increas...
If x tan 60° + cos 45° = sec 45° then the value of x2 + 1 is
What is the value of sin (B – C) cos (A – D) + sin (A – B) cos (C – D) + sin (C – A) cos (B – D)?
What is the value of (4/3) cot2 (p/6) + 3 cos2 (150o) – 4 cosec2 45o + 8 sin (p/2)?
...What is the value of [(tan 5θ + tan 3θ)/4 cos 4θ (tan 5θ – tan 3θ)]?
cot 4˚ x cot 47˚ x cot 42.3˚ x cot 43˚ x cot 47.7˚ x cot 86˚= ?
If sin 2A = cos (3A - 60o) , then find the value of sec 2A.
From a point 50 meters away from the base of a tower, the angle of elevation of the top of the tower is 30°. Find the height of the tower.
If (5sinx - cosx) = 2√2sinx, then find the value of 'tanx'
