Question
A train crosses a 360-metre-long platform in 24 seconds,
and the same train crosses a tunnel 50% longer than the platform in 33 seconds, then find the speed of train in km/h.Solution
Let the length and speed of train be ‘l’ metres and ‘x’ m/s, respectively.
Then, according to question,
(l + 360)/24 = (l + 540)/33
11l + 3960 = 8l + 4320
3l = 360
l = 120 metres
x = (l + 360)/24 = 480/24 = 20 m/s = 20×(18/5) = 72 km/h
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