Question
A train crosses a 400-metre-long platform in 25 seconds,
and the same train crosses a tunnel 25% longer than the platform in 30 seconds. Find the speed of train in km/h.Solution
Let the length and speed of train be βlβ metres and βxβ m/s, respectively.
Then, according to question,
(l + 400)/25 = (l + 500)/30
6l + 2400 = 5l + 2500
l = 100
l = 100 metres
x = (l + 400)/25 = 500/25 = 20 m/s = 20Γ(18/5) = 72 km/h
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