Question
A train crosses a 300-metre-long bridge in 20 seconds,
and the same train crosses a tunnel twice the length of the bridge in 35 seconds. Find the speed of train in km/h.Solution
Let the length and speed of train be βlβ metres and βxβ m/s, respectively.
Then, according to question,
(l + 300)/20 = (l + 600)/35
7l + 2100 = 4l + 2400
3l = 300
l = 100 metres
x = (l + 300)/20 = 400/20 = 20 m/s = 20Γ(18/5) = 72 km/h
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
5999.93 Γ· 60.005 Γ 70.002 = ? Γ 24.9
?% of 309.99 = 40.01% of 249.99 + 295.98% of 49.99
16.11 Γ 9.96 β (238.19 β 64.04 Γ 2.18) = ?
20.06% of 359.89 - 15.95 X ? + 18.07 X 14.95 = 48.87 X 6.02
2550.03 Γ· 74.98 x 49.9 = ? + 20.32
56237.05 + 10616.99 - 137.25 + 1795.33 = ?
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
30.33% of 440.08 + 45.09 Γ 5.998 β β961.09 Γ 3.990 β 189.99 = ?
44.87% of (39.85 Γ ?) β 1520.88 0.51 = 1400.8