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Distance covered by train 'A' in 25 seconds = length of train 'A'
Distance covered by train 'A' in 32 seconds = length of train 'A' + 112 metres
So, distance covered by train 'A' in (32 - 25) i.e. 7 seconds = 112 metres
So, speed of train 'A' = 112 ÷ 7 = 16 m/s
Length of train 'A' = 16 X 25 = 400 metres
Let the speed of train 'B' = 'x' m/s
When travelling in opposite directions, relative speed of train 'A' w.r.t train 'B' = (16 + x) m/s
We have, (400 + 200) ÷ (16 + x) = 20
(16 + x) = 600 ÷ 20 = 30
So, x = 30 - 16 = 14
Therefore, speed of train 'B' = 14 m/s
458.32-563.32+659.32=?
(8 x 9) ÷ 5 + ?2 = 23.4
142 + 233 + ?2 – 301 = 450 + 65
72 + 122 - 25% of 600 = ?
4/5 + 6/7 × 14/42 ÷ 24/35 = ?
Simplify the expression:
(9x² - 25) / (3x + 5)
0.3 × 0.2 + 0.4 × 0.3 + ? = 413.18
5490 ÷ 15 × 18 + 450 = ?
(34.88% of 699.79) + 40.030 × 17.88 of 11.86 + 16.21 =? + (7.22)²