Train 'A' takes 25 seconds to pass a stationary pole and

Solution

Distance covered by train 'A' in 25 seconds = length of train 'A'

Distance covered by train 'A' in 32 seconds = length of train 'A' + 112 metres

So, distance covered by train 'A' in (32 - 25) i.e. 7 seconds = 112 metres

So, speed of train 'A' = 112 ÷ 7 = 16 m/s

Length of train 'A' = 16 X 25 = 400 metres

Let the speed of train 'B' = 'x' m/s

When travelling in opposite directions, relative speed of train 'A' w.r.t train 'B' = (16 + x) m/s

We have, (400 + 200) ÷ (16 + x) = 20

(16 + x) = 600 ÷ 20 = 30

So, x = 30 - 16 = 14

Therefore, speed of train 'B' = 14 m/s