Question
A train 'D' departed from Lucknow
at 7:00 PM, traveling at a speed of 66 km/h, and reached Kolkata. Meanwhile, Train 'C' left Kolkata at 9:00 PM on the same day, moving at a speed of 58 km/h, and headed towards Lucknow. The two trains met at 2:00 AM. Which of the following statements is accurate? I. The time required for Train 'B', which travels at a speed of 47 km/h, to reach Kolkata from Lucknow is 'p hours. II. After meeting, the difference in the distance covered by Train 'D' and Train 'C' in exactly 2 hours is 'q' km. III. If Train 'C' maintained a constant speed for 12 hours, the distance it covered in that period is 'r' km less than the total distance between Lucknow and Kolkata.Solution
ATQ, Distance between Lucknow & Kolkata = 66 × 7 + 58 × 5 = 462 + 290 = 752 km I) p = 752/47 = 16 II) q = (66 - 58) × 2 = 8 × 2 = 16 III) r = 752 - 12 × 58 = 752 - 696 = 56 1.5p + 2q = r 1.5 × 16 + 2 × 16 = 56 24 + 32 = 56 56 = 56 LHS = RHS 1.5p + 2q = r
What will come in the place of question mark (?) in the given expression?
(63 - ?) ÷ 5 + √625 = 19 X (9 - 6)
- What will come in place of (?), in the given expression.
(4² + 6²) × 2 = ? What will come in the place of question mark (?) in the given expression?
(40/25) X 80 - ? = 45% of 300 - 5525.6% of 250 + √? = 119
1220 ÷ 61 ÷ 5 + 450 of 20% - 70 = √ ?
Simplify the expression:
(5x + 15) / (x² + 3x)
What will come in the place of question mark (?) in the given expression?Â
435 ÷ 29 X 792 ÷ 44 = √(? + 14) + 35 + 221 ÷ 17
...192.251 + 326.233 + 125.021 + 19.273 = ?
36% of 640 – 12.5% of 352 + 25% of 640 = ? – 48% of 432
Simplify the following expressions and choose the correct option.
18 * 15 - {3/5 of 250 + 72}
