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Let’s assume the speeds of train A and B are ‘Sa‘ and ‘Sb‘ respectively.
The ratio between the lengths of train A and B is 9:7 respectively.
Let’s assume the lengths of train A and B are 9y and 7y respectively.
Train B which is ‘d’ meter long can cross a pole in 35 seconds.
So d = 7y
7y = 35xSb
y = 5xSb Eq.(i)
Train A can cross a platform of (d+10) meter long in (t+45) seconds.
(7y+10) = (t+45)xSa Eq.(ii)
Train B can cross train A in (3t-70) seconds. If the difference between the speeds of both trains is 4 m/s.
(9y+7y)/(3t-70) = 4
16y = 4(3t-70)
4y =(3t-70) Eq.(iii)
In Eq.(i), Eq.(ii) and Eq.(iii), there are a total of four variables. We cannot determine the value of ‘t’ from the given information.
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