Question
Two trains started from stations ‘A’ and ‘B’ at
same time and started travelling towards each other at speeds of 80 km/hr and 70 km/hr, respectively. At the time of their meeting, the faster train has travelled 145 km more than the slower train. Find the distance between the stations ‘A and ‘B’.Solution
Let the distance travelled by slower train be ‘x’ km So, distance travelled by faster train = ‘x + 145’ km ATQ, (x/70) = {(x + 145)/80} Or, 80x = 70x + 10150 Or, 10x = 10150 So, x = 1015 Total distance between station ‘A’ and station ‘B’ = (1015 + 1015 + 145) = 2175 km
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