Question
Two trains started from stations βAβ and βBβ at
same time and started travelling towards each other at speeds of 80 km/hr and 70 km/hr, respectively. At the time of their meeting, the faster train has travelled 145 km more than the slower train. Find the distance between the stations βA and βBβ.Solution
Let the distance travelled by slower train be βxβ km So, distance travelled by faster train = βx + 145β km ATQ, (x/70) = {(x + 145)/80} Or, 80x = 70x + 10150 Or, 10x = 10150 So, x = 1015 Total distance between station βAβ and station βBβ = (1015 + 1015 + 145) = 2175 km
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