Question
What is the surface area of a sphere if its volume is 4,851
cm³?Solution
Let, the radius of the sphere be 'r' cm.
ATQ,
(4/3) X (22/7) X r 3 = 4851
Or, r 3 = 4851 X (3/4) X (7/22)
Or, r 3 = 441 X 21 X (1/8)
So, r = (21/2) = 10.5 cm
So, the surface area of the sphere = 4 X (22/7) X (21/2) X (21/2) = 1,386 cm 2
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