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Let the distance travelled by slower train be ‘x’ km So, distance travelled by faster train = ‘x + 200’ km ATQ, (x/20) = {(x + 200)/30} Or, 30x = 20x + 4000 Or, 10x = 4000 So, x = 400 Total distance between station ‘A’ and station ‘B’ = (400 + 400 + 200) = 1000 km
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