Question
A shopkeeper marked an article P% above its cost price and sold it for Rs. 730 after giving a discount of 25%. If the shopkeeper had a loss of 10% on the whole transaction, then find the value of ‘P’. (approximate value)
Solution
Marked price of article = 730/0.75 = Rs. 973.333 Cost price of the article = 730/0.90 = Rs. 811.11 So, P = [(973.333 – 811.11)/811.11] × 100 = 20% (approx)
More ESIC Part B Questions
- Match the following leaders with the journals or newspapers they founded or contributed to:
- If the old man kicked the bucket. The above sentence means:
- Which of the following is not a type of equity?
- He made significant contributions as Project Director to develop India’s first indigenous Satellite Launch Vehicle (SLV-III) which successfully injected th...
- The role of Tatia Tope in the 1857 mutiny: 1.   He was commander-in-chief of the army of Nana Saheb and 2.   He has to organize Bhils of Panchmahal regio...
- The circumference of a circle is 55 cm and the length of the rectangle is 8 times the radius of the circle. Find the area (in cm2) of the rectangle, if the...
- Raksha Kavach' is
- Which of the following devices does NOT make use of current carrying conductor in a magnetic field?
- Which of the following machinery cannot be said to be bipartite machinery?
- Which of the following statement/s is/are correct regarding Securities and exchange board of India?        I.           It was established by an act of t...