Question
400 metre long train βAβ is running with a speed of
61.2 km/hr. Train βBβ which is 442 metre long is running with a speed of 90 km/h in opposite direction of train βAβ. For how much time, the smaller train is completely obscured by the larger train when they cross each other?Solution
Length of smaller train = 400 metre Speed of smaller train = 61.2 Γ (5/18) = 17 m/s Length of bigger train = 442 metres Speed of bigger train = 90 Γ (5/18) = 25 m/s Since, the smaller train is completely obscured by larger train, therefore, extra length of larger train = 442 β 400 = 42 metres Relative speed of trains βAβ and βB β= 17 + 25 = 42 m/s (Since, the trains are running in opposite direction) Required time = 42/42 = 1 second
√3598 × √(230 ) ÷ √102= ?
15% of 2400 + (β 484 β β 256) = ?
(13)2Β - 3127 Γ· 59 = ? x 4
6269 + 0.25 × 444 + 0.8 × 200 = ? × 15
...(53 + 480 Γ· 4)% of 20 = ?% of 70
Find the simplified value of the following expression:
62 + 122 Γ 5 - {272 + 162 - 422}
(15 Γ 225) Γ· (45 Γ 5) + 480 = ? + 25% of 1240
β [? x 11 + (β 1296)] = 16
11 Γ 25 + 12 Γ 15 + 14 Γ 20 + 15 = ?