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    Question

    TYPE 2

    A 300 m long train crosses a platform twice its length

    in 3 min. Find the speed of the train.
    A 8 m/s Correct Answer Incorrect Answer
    B 5 m/s Correct Answer Incorrect Answer
    C 11 m/s Correct Answer Incorrect Answer
    D 7 m/s Correct Answer Incorrect Answer
    E 9 m/s Correct Answer Incorrect Answer

    Solution

    Speed of train = (Length of train + Length of Platform)/Required time Length of train = 300 m Crossing time of platform = 3 × 60 = 180 sec Length of platform = 300 × 2 = 600 m Let the speed of train be x. Speed of train = (300 + 600)/180 ⇒  x = 900/180 = 5 m/s

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