Question
A train 125 m long passes a man running at 5 km/hr in
the same direction in which the train is going, in 10 seconds. The speed of the train is:Solution
Speed of the train relative to man = (125/10) m/sec = (25/2) m/sec.
[(25/2) × (18/5)] km/hr = 45 km/hr.
Let the speed of the train be 'S' km/hr.
Then, relative speed = (S - 5) km/hr.
S - 5 = 45 => S = 50 km/hr.
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