A train started from station P and preceded towards station Q at a speed of 60 km/h. 35 minutes later, another train started from station Q and preceded towards station P at 100 km/h. If the distance between the two stations is 675 km, at what distance from station P will the trains meet?
Let the train will meet ‘t’ hours after the train from station Q started Distance travelled by train started from station P = 60 x 35/60 km Distance travelled by train started from station Q = (60 + 100) x t km Total distance between station P and Q = 675 km Now, 60 x (35/60) + (60 + 100) x t = 675 ⇒ 35 + 160t = 675 ⇒ 160t = 675 – 35 = 640 ⇒ t = 640/160 = 4 hours Distance travelled by train starting from station P at all meeting point = 35 + 60 x 4 = 275 km
Quantity I. value of m is 5/6 of x. Given that x - √576 = 0
Quantity II. Value of y in √15 y - 5 = 25
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