Question
A train started from station P and preceded towards
station Q at a speed of 90 km/h. 42 minutes later, another train started from station Q and preceded towards station P at 100 km/h. If the distance between the two stations is 443 km, at what distance from station P will the trains meet?Solution
Let the train will meet ‘t’ hours after the train from station Q started Distance travelled by train started from station P = 90 x 42/60 km Distance travelled by train started from station Q = (90 + 100) x t km Total distance between station P and Q = 443 km Now, 90 x (42/60) + (90 + 100) x t = 443 ⇒ 90 + 190t = 443 ⇒ 190t = 443 – 63 = 380 ⇒ t = 380/190 = 2 hours Distance travelled by train starting from station P at all meeting point = 63 + 90 x 2 = 243 km
(20% of 15% of 600 – 6) × 5 + 84 = ?2Â
180 ÷ 3 of 2 = 102 – ?
The sum of two numbers is 16 and their product is 63. The sum of their reciprocal is equal to:
∛21952 × 44 = ? × 14
What will come in the place of question mark (?) in the given expression?
(√1089 + 84 ÷ 2) % of 348 = 416 - ?
What will come in the place of question mark (?) in the given expression?
{(16 × 25) ÷ 32} × 12 = ? – 200
- What will come in place of (?) in the given expression.
(18 × 2) + (72 ÷ 3) – 16 = ? 13 X √? + 256 ÷ 4 = 30% of 900 - 50
1365 ÷ 15 + (? ÷ 5) = 62 × 3.5
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