Question
A train started from station P and preceded towards
station Q at a speed of 75 km/h. 36 minutes later, another train started from station Q and preceded towards station P at 100 km/h. If the distance between the two stations is 570 km, at what distance from station P will the trains meet?Solution
Let the train will meet ‘t’ hours after the train from station Q started Distance travelled by train started from station P = 75 x 36/60 km Distance travelled by train started from station Q = (75 + 100) x t km Total distance between station P and Q = 570 km Now, 75 x (36/60) + (75 + 100) x t = 570 ⇒ 45 + 175t = 570 ⇒ 175t = 570 – 45 = 525 ⇒ t = 525/175 = 3 hours Distance travelled by train starting from station P at all meeting point = 45 + 75 x 3 = 270 km
2380.03 ÷ 84.98 x 39.9 = ? + 15.32
The speed of the boat in still water is 20% less than the speed of the boat in downstream. The time taken by the boat to cover 780 km distance in upstre...
(1709.87 ÷ 38.09) + (768.11 ÷ 23.87) + (6599.81 ÷ 88.06) = ?
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
56.02% of 1499.98 + 64.04% of 2501.01 = ? + 25.05 × 49.98 + 6.063
25.22% of (59.9 × 8.01) + 69.97 =?Â
18.22 × 11.99 + 154.15 = ?
40.22 of 249.98% + 459.99 ÷ 23.18 = ?
648.13 ÷ 35.86 + 28.88 × 13.13 – 39.92% of 900.19 = ?
(284.85 ÷ 15.09) x 2.22 + 51.17 = 157.69 - ?
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