Question
A train started from station P and preceded towards
station Q at a speed of 75 km/h. 36 minutes later, another train started from station Q and preceded towards station P at 100 km/h. If the distance between the two stations is 570 km, at what distance from station P will the trains meet?Solution
Let the train will meet ‘t’ hours after the train from station Q started Distance travelled by train started from station P = 75 x 36/60 km Distance travelled by train started from station Q = (75 + 100) x t km Total distance between station P and Q = 570 km Now, 75 x (36/60) + (75 + 100) x t = 570 ⇒ 45 + 175t = 570 ⇒ 175t = 570 – 45 = 525 ⇒ t = 525/175 = 3 hours Distance travelled by train starting from station P at all meeting point = 45 + 75 x 3 = 270 km
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