Let the length of the first train is x metre Length of second train = 3x/4 Therefore, (62 + 28) x 5/18 = {x + (3x/4)}/14 ⇒ 90 x 5/18 = (7x/4)/14 ⇒ x = 200 m Therefore, let the length of the platform be y metre ⇒ 62 x 5/18 = (200 + y)/36 ⇒ 620 = 200 + y ⇒ y = 620 – 200 = 420 m
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