Question
Train P travelling at 62 km/hr crosses another train Q,
having three fourth of its length and travelling in opposite direction at 28 km/hr in 14 seconds. Train P passed a railway platform in 36 seconds. Find the length of platform.Solution
Let the length of the first train is x metre Length of second train = 3x/4 Therefore, (62 + 28) x 5/18 = {x + (3x/4)}/14 β 90 x 5/18 = (7x/4)/14 β x = 200 m Therefore, let the length of the platform be y metre β 62 x 5/18 = (200 + y)/36 β 620 = 200 + y β y = 620 β 200 = 420 m
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