Train P travelling at 60 km/hr crosses another train Q, having three fourth of its length and travelling in opposite direction at 48 km/hr in 14 seconds. Train P passed a railway platform in 24 seconds. Find the length of platform.
Let the length of the first train is x metre Length of second train = 3x/4 Therefore, (60 + 48) x 5/18 = {x + (3x/4)}/14 ⇒ 108 x 5/18 = (7x/4)/14 ⇒ x = 240 m Therefore, let the length of the platform be y metre ⇒ 60 x 5/18 = (240 + y)/24 ⇒ 400 = 240 + y ⇒ y = 400 – 240 = 160 m
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